Calculation Of MB With Chemical Reaction With Example

 A small scale semibatch reactor unit produces 5000 kg/day of Chloroacetic acid. It uses 4536kg/day of chlorine gas. But 263kg/day of dichloro acetic acid also formed. Here we will find the  percent conversion, percent yield of Chloroacetic acid and selectivity.

Reactions :

   

       CH₃COOH + Cl₂  ------- ClCH₂COOH + HCl

       CH₃COOH + 2Cl₂ ------- Cl₂CHCOOH + 2HCl 

SOLUTION :

 Number of Cl₂ Charged = 4536 / 71

                                           = 63.9 kmol

Number of moles of  Cl2 used for 1st reaction

                                                         = 5000 / 94.5

                                                         = 52.9 kmol

Number of moles of Cl2 used for 2nd reaction
                                                         = (263 / 129) * 2
                                                         = 4.1 kmol

Percent Conversion
                          = Total Cl2 used / Total Cl2 taken
                          = (52.9+4.1) / 63.9 * 100
                          = 89.2 %

Percent Yield = 52.9 / (52.9 + 4.1) * 100
                           = 92.85%

Selectivity = 52.9 / 4.1 * 100
                  = 12.97